Optimal. Leaf size=205 \[ \frac {3 i x^2}{2 b^2}+\frac {x^3}{2 b}-\frac {i x^4}{4}-\frac {3 x \log \left (1+e^{2 i (a+b x)}\right )}{b^3}+\frac {x^3 \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac {3 i \text {PolyLog}\left (2,-e^{2 i (a+b x)}\right )}{2 b^4}-\frac {3 i x^2 \text {PolyLog}\left (2,-e^{2 i (a+b x)}\right )}{2 b^2}+\frac {3 x \text {PolyLog}\left (3,-e^{2 i (a+b x)}\right )}{2 b^3}+\frac {3 i \text {PolyLog}\left (4,-e^{2 i (a+b x)}\right )}{4 b^4}-\frac {3 x^2 \tan (a+b x)}{2 b^2}+\frac {x^3 \tan ^2(a+b x)}{2 b} \]
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Rubi [A]
time = 0.21, antiderivative size = 205, normalized size of antiderivative = 1.00, number of steps
used = 13, number of rules used = 10, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.833, Rules used = {3801, 3800,
2221, 2317, 2438, 30, 2611, 6744, 2320, 6724} \begin {gather*} \frac {3 i \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{2 b^4}+\frac {3 i \text {Li}_4\left (-e^{2 i (a+b x)}\right )}{4 b^4}+\frac {3 x \text {Li}_3\left (-e^{2 i (a+b x)}\right )}{2 b^3}-\frac {3 x \log \left (1+e^{2 i (a+b x)}\right )}{b^3}-\frac {3 i x^2 \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{2 b^2}-\frac {3 x^2 \tan (a+b x)}{2 b^2}+\frac {x^3 \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac {x^3 \tan ^2(a+b x)}{2 b}+\frac {3 i x^2}{2 b^2}+\frac {x^3}{2 b}-\frac {i x^4}{4} \end {gather*}
Antiderivative was successfully verified.
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Rule 30
Rule 2221
Rule 2317
Rule 2320
Rule 2438
Rule 2611
Rule 3800
Rule 3801
Rule 6724
Rule 6744
Rubi steps
\begin {align*} \int x^3 \tan ^3(a+b x) \, dx &=\frac {x^3 \tan ^2(a+b x)}{2 b}-\frac {3 \int x^2 \tan ^2(a+b x) \, dx}{2 b}-\int x^3 \tan (a+b x) \, dx\\ &=-\frac {i x^4}{4}-\frac {3 x^2 \tan (a+b x)}{2 b^2}+\frac {x^3 \tan ^2(a+b x)}{2 b}+2 i \int \frac {e^{2 i (a+b x)} x^3}{1+e^{2 i (a+b x)}} \, dx+\frac {3 \int x \tan (a+b x) \, dx}{b^2}+\frac {3 \int x^2 \, dx}{2 b}\\ &=\frac {3 i x^2}{2 b^2}+\frac {x^3}{2 b}-\frac {i x^4}{4}+\frac {x^3 \log \left (1+e^{2 i (a+b x)}\right )}{b}-\frac {3 x^2 \tan (a+b x)}{2 b^2}+\frac {x^3 \tan ^2(a+b x)}{2 b}-\frac {(6 i) \int \frac {e^{2 i (a+b x)} x}{1+e^{2 i (a+b x)}} \, dx}{b^2}-\frac {3 \int x^2 \log \left (1+e^{2 i (a+b x)}\right ) \, dx}{b}\\ &=\frac {3 i x^2}{2 b^2}+\frac {x^3}{2 b}-\frac {i x^4}{4}-\frac {3 x \log \left (1+e^{2 i (a+b x)}\right )}{b^3}+\frac {x^3 \log \left (1+e^{2 i (a+b x)}\right )}{b}-\frac {3 i x^2 \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{2 b^2}-\frac {3 x^2 \tan (a+b x)}{2 b^2}+\frac {x^3 \tan ^2(a+b x)}{2 b}+\frac {3 \int \log \left (1+e^{2 i (a+b x)}\right ) \, dx}{b^3}+\frac {(3 i) \int x \text {Li}_2\left (-e^{2 i (a+b x)}\right ) \, dx}{b^2}\\ &=\frac {3 i x^2}{2 b^2}+\frac {x^3}{2 b}-\frac {i x^4}{4}-\frac {3 x \log \left (1+e^{2 i (a+b x)}\right )}{b^3}+\frac {x^3 \log \left (1+e^{2 i (a+b x)}\right )}{b}-\frac {3 i x^2 \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{2 b^2}+\frac {3 x \text {Li}_3\left (-e^{2 i (a+b x)}\right )}{2 b^3}-\frac {3 x^2 \tan (a+b x)}{2 b^2}+\frac {x^3 \tan ^2(a+b x)}{2 b}-\frac {(3 i) \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{2 b^4}-\frac {3 \int \text {Li}_3\left (-e^{2 i (a+b x)}\right ) \, dx}{2 b^3}\\ &=\frac {3 i x^2}{2 b^2}+\frac {x^3}{2 b}-\frac {i x^4}{4}-\frac {3 x \log \left (1+e^{2 i (a+b x)}\right )}{b^3}+\frac {x^3 \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac {3 i \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{2 b^4}-\frac {3 i x^2 \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{2 b^2}+\frac {3 x \text {Li}_3\left (-e^{2 i (a+b x)}\right )}{2 b^3}-\frac {3 x^2 \tan (a+b x)}{2 b^2}+\frac {x^3 \tan ^2(a+b x)}{2 b}+\frac {(3 i) \text {Subst}\left (\int \frac {\text {Li}_3(-x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{4 b^4}\\ &=\frac {3 i x^2}{2 b^2}+\frac {x^3}{2 b}-\frac {i x^4}{4}-\frac {3 x \log \left (1+e^{2 i (a+b x)}\right )}{b^3}+\frac {x^3 \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac {3 i \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{2 b^4}-\frac {3 i x^2 \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{2 b^2}+\frac {3 x \text {Li}_3\left (-e^{2 i (a+b x)}\right )}{2 b^3}+\frac {3 i \text {Li}_4\left (-e^{2 i (a+b x)}\right )}{4 b^4}-\frac {3 x^2 \tan (a+b x)}{2 b^2}+\frac {x^3 \tan ^2(a+b x)}{2 b}\\ \end {align*}
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Mathematica [A]
time = 6.73, size = 366, normalized size = 1.79 \begin {gather*} \frac {1}{4} i e^{i a} \left (-x^4+\left (1+e^{-2 i a}\right ) x^4-\frac {e^{-2 i a} \left (1+e^{2 i a}\right ) \left (2 b^4 x^4+4 i b^3 x^3 \log \left (1+e^{2 i (a+b x)}\right )+6 b^2 x^2 \text {PolyLog}\left (2,-e^{2 i (a+b x)}\right )+6 i b x \text {PolyLog}\left (3,-e^{2 i (a+b x)}\right )-3 \text {PolyLog}\left (4,-e^{2 i (a+b x)}\right )\right )}{2 b^4}\right ) \sec (a)+\frac {x^3 \sec ^2(a+b x)}{2 b}-\frac {3 \csc (a) \left (b^2 e^{-i \text {ArcTan}(\cot (a))} x^2-\frac {\cot (a) \left (i b x (-\pi -2 \text {ArcTan}(\cot (a)))-\pi \log \left (1+e^{-2 i b x}\right )-2 (b x-\text {ArcTan}(\cot (a))) \log \left (1-e^{2 i (b x-\text {ArcTan}(\cot (a)))}\right )+\pi \log (\cos (b x))-2 \text {ArcTan}(\cot (a)) \log (\sin (b x-\text {ArcTan}(\cot (a))))+i \text {PolyLog}\left (2,e^{2 i (b x-\text {ArcTan}(\cot (a)))}\right )\right )}{\sqrt {1+\cot ^2(a)}}\right ) \sec (a)}{2 b^4 \sqrt {\csc ^2(a) \left (\cos ^2(a)+\sin ^2(a)\right )}}-\frac {3 x^2 \sec (a) \sec (a+b x) \sin (b x)}{2 b^2}-\frac {1}{4} x^4 \tan (a) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.11, size = 251, normalized size = 1.22
method | result | size |
risch | \(\frac {3 i x^{2}}{b^{2}}+\frac {x^{2} \left (2 b x \,{\mathrm e}^{2 i \left (b x +a \right )}-3 i {\mathrm e}^{2 i \left (b x +a \right )}-3 i\right )}{b^{2} \left ({\mathrm e}^{2 i \left (b x +a \right )}+1\right )^{2}}+\frac {3 i \polylog \left (2, -{\mathrm e}^{2 i \left (b x +a \right )}\right )}{2 b^{4}}-\frac {2 i a^{3} x}{b^{3}}+\frac {3 i \polylog \left (4, -{\mathrm e}^{2 i \left (b x +a \right )}\right )}{4 b^{4}}-\frac {3 i x^{2} \polylog \left (2, -{\mathrm e}^{2 i \left (b x +a \right )}\right )}{2 b^{2}}+\frac {3 i a^{2}}{b^{4}}-\frac {i x^{4}}{4}+\frac {6 i a x}{b^{3}}+\frac {2 a^{3} \ln \left ({\mathrm e}^{i \left (b x +a \right )}\right )}{b^{4}}-\frac {3 x \ln \left ({\mathrm e}^{2 i \left (b x +a \right )}+1\right )}{b^{3}}+\frac {3 x \polylog \left (3, -{\mathrm e}^{2 i \left (b x +a \right )}\right )}{2 b^{3}}-\frac {3 i a^{4}}{2 b^{4}}+\frac {x^{3} \ln \left ({\mathrm e}^{2 i \left (b x +a \right )}+1\right )}{b}-\frac {6 a \ln \left ({\mathrm e}^{i \left (b x +a \right )}\right )}{b^{4}}\) | \(251\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Both result and optimal contain complex but leaf count of result is larger than
twice the leaf count of optimal. 1205 vs. \(2 (163) = 326\).
time = 0.67, size = 1205, normalized size = 5.88 \begin {gather*} \frac {a^{3} {\left (\frac {1}{\sin \left (b x + a\right )^{2} - 1} - \log \left (\sin \left (b x + a\right )^{2} - 1\right )\right )} - \frac {2 \, {\left (3 \, {\left (b x + a\right )}^{4} - 12 \, {\left (b x + a\right )}^{3} a + 18 \, {\left (b x + a\right )}^{2} a^{2} + 36 \, a^{2} - 4 \, {\left (4 \, {\left (b x + a\right )}^{3} - 9 \, {\left (b x + a\right )}^{2} a + 9 \, {\left (a^{2} - 1\right )} {\left (b x + a\right )} + {\left (4 \, {\left (b x + a\right )}^{3} - 9 \, {\left (b x + a\right )}^{2} a + 9 \, {\left (a^{2} - 1\right )} {\left (b x + a\right )} + 9 \, a\right )} \cos \left (4 \, b x + 4 \, a\right ) + 2 \, {\left (4 \, {\left (b x + a\right )}^{3} - 9 \, {\left (b x + a\right )}^{2} a + 9 \, {\left (a^{2} - 1\right )} {\left (b x + a\right )} + 9 \, a\right )} \cos \left (2 \, b x + 2 \, a\right ) - {\left (-4 i \, {\left (b x + a\right )}^{3} + 9 i \, {\left (b x + a\right )}^{2} a + 9 \, {\left (-i \, a^{2} + i\right )} {\left (b x + a\right )} - 9 i \, a\right )} \sin \left (4 \, b x + 4 \, a\right ) - 2 \, {\left (-4 i \, {\left (b x + a\right )}^{3} + 9 i \, {\left (b x + a\right )}^{2} a + 9 \, {\left (-i \, a^{2} + i\right )} {\left (b x + a\right )} - 9 i \, a\right )} \sin \left (2 \, b x + 2 \, a\right ) + 9 \, a\right )} \arctan \left (\sin \left (2 \, b x + 2 \, a\right ), \cos \left (2 \, b x + 2 \, a\right ) + 1\right ) + 3 \, {\left ({\left (b x + a\right )}^{4} - 4 \, {\left (b x + a\right )}^{3} a + 6 \, {\left (a^{2} - 2\right )} {\left (b x + a\right )}^{2} + 24 \, {\left (b x + a\right )} a\right )} \cos \left (4 \, b x + 4 \, a\right ) + 6 \, {\left ({\left (b x + a\right )}^{4} - 4 \, {\left (b x + a\right )}^{3} {\left (a - i\right )} + 6 \, {\left (a^{2} - 2 i \, a - 1\right )} {\left (b x + a\right )}^{2} + 12 \, {\left (i \, a^{2} + a\right )} {\left (b x + a\right )} + 6 \, a^{2}\right )} \cos \left (2 \, b x + 2 \, a\right ) + 6 \, {\left (4 \, {\left (b x + a\right )}^{2} - 6 \, {\left (b x + a\right )} a + 3 \, a^{2} + {\left (4 \, {\left (b x + a\right )}^{2} - 6 \, {\left (b x + a\right )} a + 3 \, a^{2} - 3\right )} \cos \left (4 \, b x + 4 \, a\right ) + 2 \, {\left (4 \, {\left (b x + a\right )}^{2} - 6 \, {\left (b x + a\right )} a + 3 \, a^{2} - 3\right )} \cos \left (2 \, b x + 2 \, a\right ) + {\left (4 i \, {\left (b x + a\right )}^{2} - 6 i \, {\left (b x + a\right )} a + 3 i \, a^{2} - 3 i\right )} \sin \left (4 \, b x + 4 \, a\right ) + 2 \, {\left (4 i \, {\left (b x + a\right )}^{2} - 6 i \, {\left (b x + a\right )} a + 3 i \, a^{2} - 3 i\right )} \sin \left (2 \, b x + 2 \, a\right ) - 3\right )} {\rm Li}_2\left (-e^{\left (2 i \, b x + 2 i \, a\right )}\right ) + 2 \, {\left (4 i \, {\left (b x + a\right )}^{3} - 9 i \, {\left (b x + a\right )}^{2} a + 9 \, {\left (i \, a^{2} - i\right )} {\left (b x + a\right )} + {\left (4 i \, {\left (b x + a\right )}^{3} - 9 i \, {\left (b x + a\right )}^{2} a + 9 \, {\left (i \, a^{2} - i\right )} {\left (b x + a\right )} + 9 i \, a\right )} \cos \left (4 \, b x + 4 \, a\right ) + 2 \, {\left (4 i \, {\left (b x + a\right )}^{3} - 9 i \, {\left (b x + a\right )}^{2} a + 9 \, {\left (i \, a^{2} - i\right )} {\left (b x + a\right )} + 9 i \, a\right )} \cos \left (2 \, b x + 2 \, a\right ) - {\left (4 \, {\left (b x + a\right )}^{3} - 9 \, {\left (b x + a\right )}^{2} a + 9 \, {\left (a^{2} - 1\right )} {\left (b x + a\right )} + 9 \, a\right )} \sin \left (4 \, b x + 4 \, a\right ) - 2 \, {\left (4 \, {\left (b x + a\right )}^{3} - 9 \, {\left (b x + a\right )}^{2} a + 9 \, {\left (a^{2} - 1\right )} {\left (b x + a\right )} + 9 \, a\right )} \sin \left (2 \, b x + 2 \, a\right ) + 9 i \, a\right )} \log \left (\cos \left (2 \, b x + 2 \, a\right )^{2} + \sin \left (2 \, b x + 2 \, a\right )^{2} + 2 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right ) - 12 \, {\left (\cos \left (4 \, b x + 4 \, a\right ) + 2 \, \cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (4 \, b x + 4 \, a\right ) + 2 i \, \sin \left (2 \, b x + 2 \, a\right ) + 1\right )} {\rm Li}_{4}(-e^{\left (2 i \, b x + 2 i \, a\right )}) + 6 \, {\left (4 i \, b x + {\left (4 i \, b x + i \, a\right )} \cos \left (4 \, b x + 4 \, a\right ) + 2 \, {\left (4 i \, b x + i \, a\right )} \cos \left (2 \, b x + 2 \, a\right ) - {\left (4 \, b x + a\right )} \sin \left (4 \, b x + 4 \, a\right ) - 2 \, {\left (4 \, b x + a\right )} \sin \left (2 \, b x + 2 \, a\right ) + i \, a\right )} {\rm Li}_{3}(-e^{\left (2 i \, b x + 2 i \, a\right )}) + 3 \, {\left (i \, {\left (b x + a\right )}^{4} - 4 i \, {\left (b x + a\right )}^{3} a + 6 \, {\left (i \, a^{2} - 2 i\right )} {\left (b x + a\right )}^{2} + 24 i \, {\left (b x + a\right )} a\right )} \sin \left (4 \, b x + 4 \, a\right ) + 6 \, {\left (i \, {\left (b x + a\right )}^{4} + 4 \, {\left (b x + a\right )}^{3} {\left (-i \, a - 1\right )} + 6 \, {\left (i \, a^{2} + 2 \, a - i\right )} {\left (b x + a\right )}^{2} - 12 \, {\left (a^{2} - i \, a\right )} {\left (b x + a\right )} + 6 i \, a^{2}\right )} \sin \left (2 \, b x + 2 \, a\right )\right )}}{-12 i \, \cos \left (4 \, b x + 4 \, a\right ) - 24 i \, \cos \left (2 \, b x + 2 \, a\right ) + 12 \, \sin \left (4 \, b x + 4 \, a\right ) + 24 \, \sin \left (2 \, b x + 2 \, a\right ) - 12 i}}{2 \, b^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 344 vs. \(2 (163) = 326\).
time = 0.37, size = 344, normalized size = 1.68 \begin {gather*} \frac {4 \, b^{3} x^{3} \tan \left (b x + a\right )^{2} + 4 \, b^{3} x^{3} - 12 \, b^{2} x^{2} \tan \left (b x + a\right ) + 6 \, b x {\rm polylog}\left (3, \frac {\tan \left (b x + a\right )^{2} + 2 i \, \tan \left (b x + a\right ) - 1}{\tan \left (b x + a\right )^{2} + 1}\right ) + 6 \, b x {\rm polylog}\left (3, \frac {\tan \left (b x + a\right )^{2} - 2 i \, \tan \left (b x + a\right ) - 1}{\tan \left (b x + a\right )^{2} + 1}\right ) - 6 \, {\left (-i \, b^{2} x^{2} + i\right )} {\rm Li}_2\left (\frac {2 \, {\left (i \, \tan \left (b x + a\right ) - 1\right )}}{\tan \left (b x + a\right )^{2} + 1} + 1\right ) - 6 \, {\left (i \, b^{2} x^{2} - i\right )} {\rm Li}_2\left (\frac {2 \, {\left (-i \, \tan \left (b x + a\right ) - 1\right )}}{\tan \left (b x + a\right )^{2} + 1} + 1\right ) + 4 \, {\left (b^{3} x^{3} - 3 \, b x\right )} \log \left (-\frac {2 \, {\left (i \, \tan \left (b x + a\right ) - 1\right )}}{\tan \left (b x + a\right )^{2} + 1}\right ) + 4 \, {\left (b^{3} x^{3} - 3 \, b x\right )} \log \left (-\frac {2 \, {\left (-i \, \tan \left (b x + a\right ) - 1\right )}}{\tan \left (b x + a\right )^{2} + 1}\right ) - 3 i \, {\rm polylog}\left (4, \frac {\tan \left (b x + a\right )^{2} + 2 i \, \tan \left (b x + a\right ) - 1}{\tan \left (b x + a\right )^{2} + 1}\right ) + 3 i \, {\rm polylog}\left (4, \frac {\tan \left (b x + a\right )^{2} - 2 i \, \tan \left (b x + a\right ) - 1}{\tan \left (b x + a\right )^{2} + 1}\right )}{8 \, b^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{3} \tan ^{3}{\left (a + b x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int x^3\,{\mathrm {tan}\left (a+b\,x\right )}^3 \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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